What is d/(dd)(ax^3+bx^2+cx+d) ?

The solution to d/(dd)(ax^3+bx^2+cx+d) is (ax^3+bx^2+cx+d)/d

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simplify d/(dd)(ax^3+bx^2+cx+d)

simplify

\frac{d}{dd} (a x^{3} + b x^{2} + c x + d)

\frac{a x ^{3} + b x ^{2} + c x + d}{d}

Solution steps

\frac{d}{dd} (a x^{3} + b x^{2} + c x + d)

Cancel

\frac{d}{dd} : \frac{1}{d}

= \frac{1}{d} (a x^{3} + b x^{2} + c x + d)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( a x ^{3} + b x ^{2} + c x + d )}{d}

Apply rule:

1 \cdot a = a

1 \cdot (a x^{3} + b x^{2} + c x + d) = (a x^{3} + b x^{2} + c x + d)

= \frac{a x ^{3} + b x ^{2} + c x + d}{d}

\int \frac{2}{3} e^{3 x} d x

\frac{d}{d x} ((x^{3} - 2 x) (- x + 6 x^{2}))

(e^{2 x} + 9) \frac{d y}{d x} = y

\int (x^{2} + 2 x + 1) d x

f (x) = (- 25 x^{2} + 1)^{2}

What is d/(dd)(ax^3+bx^2+cx+d) ?
The solution to d/(dd)(ax^3+bx^2+cx+d) is (ax^3+bx^2+cx+d)/d