What is the derivative of (x^2/(x+4)) ?

The derivative of (x^2/(x+4)) is (x^2+8x)/((x+4)^2)

What is the first derivative of (x^2/(x+4)) ?

The first derivative of (x^2/(x+4)) is (x^2+8x)/((x+4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{2}}{x + 4})

\frac{x ^{2} + 8 x}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x ^{2}}{( x + 4 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x + 4) = 1

= \frac{2 x ( x + 4 ) - 1 \cdot x ^{2}}{( x + 4 ) ^{2}}

Simplify

\frac{2 x ( x + 4 ) - 1 \cdot x ^{2}}{( x + 4 ) ^{2}} : \frac{x ^{2} + 8 x}{( x + 4 ) ^{2}}

= \frac{x ^{2} + 8 x}{( x + 4 ) ^{2}}

(15, 0), (0, - 2)

\int \frac{x ^{2}}{36 - x ^{2}} d x

\frac{d}{d x} (\frac{x}{5})

x \to 0 lim (x (13 + \frac{5}{x}))

f (x) = e^{x} - 2

What is the derivative of (x^2/(x+4)) ?
The derivative of (x^2/(x+4)) is (x^2+8x)/((x+4)^2)
What is the first derivative of (x^2/(x+4)) ?
The first derivative of (x^2/(x+4)) is (x^2+8x)/((x+4)^2)