What is the integral of (2x)/1 ^2 ?

The integral of (2x)/1 ^2 is d^2xt^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x)/1 ^2

\int \frac{d ^{2} x}{1} d t^{2}

d^{2} x t^{2} + C

Solution steps

\int \frac{d ^{2} x}{1} d t^{2}

Integral of a constant:

\int a d x = a x

= \frac{d ^{2} x}{1} t^{2}

Simplify

= d^{2} x t^{2}

Add a constant to the solution

= d^{2} x t^{2} + C

\frac{1}{s ^{2} + \frac{s}{4}}

f (x) = \frac{x tan ^{2} ( x )}{1 + x ^{2}}

\int 3 x^{2} + 6 d x

x \to 5 lim (ln (x - 5))