What is the first derivative of e+L(x) ?

The first derivative of e+L(x) is L

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derivative of e+L(x)

\frac{d}{d x} (e + L (x))

L

Solution steps

\frac{d}{d x} (e + L (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d e}{d x} + \frac{d}{d x} (Lx)

\frac{d e}{d x} = 0

\frac{d}{d x} (Lx) = L

= 0 + L

Simplify

= L

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