What is the derivative of s(t)=3sqrt(t+1) ?

The derivative of s(t)=3sqrt(t+1) is 3/(2sqrt(t+1))

What is the first derivative of s(t)=3sqrt(t+1) ?

The first derivative of s(t)=3sqrt(t+1) is 3/(2sqrt(t+1))

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derivative of

s (t) = 3 t + 1

\frac{3}{2 t + 1}

Solution steps

\frac{d}{d t} (3 t + 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (t + 1)

Apply the chain rule:

\frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

= \frac{1}{2 t + 1} \frac{d}{d t} (t + 1)

\frac{d}{d t} (t + 1) = 1

= 3 \cdot \frac{1}{2 t + 1} \cdot 1

Simplify

3 \cdot \frac{1}{2 t + 1} \cdot 1 : \frac{3}{2 t + 1}

= \frac{3}{2 t + 1}

\frac{\partial}{\partial y} (x^{2} yz - x y z^{3})

\frac{d}{d y} (\frac{y}{x})

\frac{d}{d x} (\frac{2 x ^{7} + 5 x ^{3} - 1}{4})

\int_{0}^{π} (1 + sin (x)) d x

2 y^{^{'''}} + 3 y^{^{''}} - 23 y^{^{'}} - 12 y = 0

What is the derivative of s(t)=3sqrt(t+1) ?
The derivative of s(t)=3sqrt(t+1) is 3/(2sqrt(t+1))
What is the first derivative of s(t)=3sqrt(t+1) ?
The first derivative of s(t)=3sqrt(t+1) is 3/(2sqrt(t+1))