What is the derivative of 2sin(x+1) ?

The derivative of 2sin(x+1) is 2cos(x)

What is the first derivative of 2sin(x+1) ?

The first derivative of 2sin(x+1) is 2cos(x)

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\frac{d}{d x} (2 sin (x) + 1)

2 cos (x)

Solution steps

\frac{d}{d x} (2 sin (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (1) = 0

= 2 cos (x) + 0

Simplify

= 2 cos (x)

\frac{\partial}{\partial x} (- \frac{1}{2 x} + \frac{1}{2 x ^{2}})

\frac{d}{d x} (x^{4} sin (3 x))

\int \frac{6}{x + 1} d x

y = x sin (\frac{3}{x})

\int \frac{x ^{7}}{x ^{4} - 3} d x

What is the derivative of 2sin(x+1) ?
The derivative of 2sin(x+1) is 2cos(x)
What is the first derivative of 2sin(x+1) ?
The first derivative of 2sin(x+1) is 2cos(x)