What is the derivative of e^{2xy} ?

The derivative of e^{2xy} is e^{2xy}*2(y+x(dy)/(dx))

What is the first derivative of e^{2xy} ?

The first derivative of e^{2xy} is e^{2xy}*2(y+x(dy)/(dx))

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\frac{d}{d x} (e^{2 x y})

e^{2 x y} \cdot 2 (y + x \frac{d y}{d x})

Solution steps

\frac{d}{d x} (e^{2 x y})

Apply the chain rule:

e^{2 x y} \frac{d}{d x} (2 x y)

= e^{2 x y} \frac{d}{d x} (2 x y)

\frac{d}{d x} (2 x y) = 2 (y + x \frac{d y}{d x})

= e^{2 x y} \cdot 2 (y + x \frac{d y}{d x})

f (x) = x^{2} (1 - 4 x)

f (x) = x^{3} - 6 x^{2} - 34 x + 40, at x = - 3

\int_{0}^{7} x 49 - x^{2} d x

\int_{0}^{2} x (x^{2} - 1)^{3} d x

\frac{\partial}{\partial x} (x^{2} y + 4 x^{4} y)

What is the derivative of e^{2xy} ?
The derivative of e^{2xy} is e^{2xy}*2(y+x(dy)/(dx))
What is the first derivative of e^{2xy} ?
The first derivative of e^{2xy} is e^{2xy}*2(y+x(dy)/(dx))