What is the derivative of ((1/x+1/(x^2))/(x-1)) ?

The derivative of ((1/x+1/(x^2))/(x-1)) is (-2x^2-2x+2)/(x^3(x-1)^2)

What is the first derivative of ((1/x+1/(x^2))/(x-1)) ?

The first derivative of ((1/x+1/(x^2))/(x-1)) is (-2x^2-2x+2)/(x^3(x-1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{( \frac{1}{x} + \frac{1}{x ^{2}} )}{x - 1})

\frac{- 2 x ^{2} - 2 x + 2}{x ^{3} ( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( \frac{1}{x} + \frac{1}{x ^{2}} )}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( \frac{1}{x} + \frac{1}{x ^{2}} ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) ( \frac{1}{x} + \frac{1}{x ^{2}} )}{( x - 1 ) ^{2}}

\frac{d}{d x} (\frac{1}{x} + \frac{1}{x ^{2}}) = - \frac{1}{x ^{2}} - \frac{2}{x ^{3}}

\frac{d}{d x} (x - 1) = 1

= \frac{( - \frac{1}{x ^{2}} - \frac{2}{x ^{3}} ) ( x - 1 ) - 1 \cdot ( \frac{1}{x} + \frac{1}{x ^{2}} )}{( x - 1 ) ^{2}}

Simplify

\frac{( - \frac{1}{x ^{2}} - \frac{2}{x ^{3}} ) ( x - 1 ) - 1 \cdot ( \frac{1}{x} + \frac{1}{x ^{2}} )}{( x - 1 ) ^{2}} : \frac{- 2 x ^{2} - 2 x + 2}{x ^{3} ( x - 1 ) ^{2}}

= \frac{- 2 x ^{2} - 2 x + 2}{x ^{3} ( x - 1 ) ^{2}}

\frac{d y}{d x} = 1 - e^{y - x + 5}

\int_{0}^{1} 6 cos (3 x) d x

x \to 1 - lim (\frac{2}{ln ( x )})

(0, 9), (7, 4)

\frac{d}{d x} (7 x^{2} tan (x))

What is the derivative of ((1/x+1/(x^2))/(x-1)) ?
The derivative of ((1/x+1/(x^2))/(x-1)) is (-2x^2-2x+2)/(x^3(x-1)^2)
What is the first derivative of ((1/x+1/(x^2))/(x-1)) ?
The first derivative of ((1/x+1/(x^2))/(x-1)) is (-2x^2-2x+2)/(x^3(x-1)^2)