What is area y=(4x)/(1+x^2),y=(4x^2)/(1+x^3) ?

The answer to area y=(4x)/(1+x^2),y=(4x^2)/(1+x^3) is 2/3 ln(2)

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area y=(4x)/(1+x^2),y=(4x^2)/(1+x^3)

area

y = \frac{4 x}{1 + x ^{2}}, y = \frac{4 x ^{2}}{1 + x ^{3}}

\frac{2}{3} ln (2)

Decimal Notation

0.46209 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{4 x}{1 + x ^{2}} - \frac{4 x ^{2}}{1 + x ^{3}} d x

Solve

\int_{0}^{1} \frac{4 x}{1 + x ^{2}} - \frac{4 x ^{2}}{1 + x ^{3}} d x : \frac{2}{3} ln (2)

The area is:

= \frac{2}{3} ln (2)

\frac{\partial}{\partial x} (4 a x^{4} + 7 b (x, t) t^{3})

y = \frac{4 + x f ( x )}{x}

\int x e^{- 2} + e x^{- 2} d x

\frac{\partial}{\partial z} (x y^{2} z^{3})

arctan (\frac{x - 1}{x + 1})

What is area y=(4x)/(1+x^2),y=(4x^2)/(1+x^3) ?
The answer to area y=(4x)/(1+x^2),y=(4x^2)/(1+x^3) is 2/3 ln(2)