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Popular >

area y=x^2-1,y=x+1

Solution

area

y = x^{2} - 1, y = x + 1

Solution

\frac{9}{2}

+1

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} x^{2} - 1 - (x + 1) d x

Solve

\int_{- 1}^{2} x^{2} - 1 - (x + 1) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Popular Examples

derivative of ln(x^4+27)

\frac{d}{d x} (ln (x^{4} + 27))

integral of 1/(9x^3)

\int \frac{1}{9 x ^{3}} d x

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\int_{1.5}^{2} \frac{2 x}{3} d x

4 y^{^{''}} + 10 y = 0

limit as x approaches 2-of sqrt(x-2)

x \to 2 - lim (x - 2)

Frequently Asked Questions (FAQ)

What is area y=x^2-1,y=x+1 ?
The answer to area y=x^2-1,y=x+1 is 9/2