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Popular >

x(x-2)y^'+2y=0

Solution

x (x - 2) y^{^{'}} + 2 y = 0

Solution

y = \frac{c _{1} x}{x - 2}

Solution steps

x (x - 2) y^{'} (x) + 2 y = 0

Solve separable ODE:

y = \frac{c _{1} x}{x - 2}

y = \frac{c _{1} x}{x - 2}

Popular Examples

integral of (x+2)sqrt(x-2)

\int (x + 2) x - 2 d x

integral of 1/((x^4-1))

\int \frac{1}{( x ^{4} - 1 )} d x

integral from 2 to 1/x of tan^2(t)

\int_{2}^{\frac{1}{x}} tan^{2} (t) d t

tangent of f(x)=x*cot(x),\at x= pi/4 tangent of

f (x) = x \cdot cot (x), at x = \frac{π}{4}

derivative of f(x)=(x+sqrt(x))/(x^3)derivative of

f (x) = \frac{x + x}{x ^{3}}

Frequently Asked Questions (FAQ)

What is the solution for x(x-2)y^'+2y=0 ?
The solution for x(x-2)y^'+2y=0 is y=(c_{1}x)/(x-2)