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Popular >

(dy)/(dx)+1/x y=xy^2

Solution

\frac{d y}{d x} + \frac{1}{x} y = x y^{2}

Solution

y = \frac{1}{x ( - x + c _{1} )}

Solution steps

\frac{d y}{d x} + \frac{1}{x} y = x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - x + c _{1} )}

y = \frac{1}{x ( - x + c _{1} )}

Popular Examples

(dy)/(dx)+y=e^{7x}

\frac{d y}{d x} + y = e^{7 x}

y^'-5/x y=(y^5)/(x^{18)}

y^{^{'}} - \frac{5}{x} y = \frac{y ^{5}}{x ^{18}}

integral from 9 to 16 of 1/(7-sqrt(x))

\int_{9}^{16} \frac{1}{7 - x} d x

integral of (sqrt(x))/(x-16)

\int \frac{x}{x - 16} d x

sum from n=0 to infinity of n^2(x)^{n-1}

n = 0 \sum \infty n^{2} (x)^{n - 1}

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dx)+1/x y=xy^2 ?
The solution for (dy)/(dx)+1/x y=xy^2 is y= 1/(x(-x+c_{1))}