What is the integral of (-2ax)/(x^2+y^2) ?

The integral of (-2ax)/(x^2+y^2) is -2aarctan(y/x)+C

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integral of (-2ax)/(x^2+y^2)

\int \frac{- 2 a x}{x ^{2} + y ^{2}} d y

- 2 a arctan (\frac{y}{x}) + C

Solution steps

\int \frac{- 2 a x}{x ^{2} + y ^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 a x \cdot \int \frac{1}{x ^{2} + y ^{2}} d y

Apply Integral Substitution

= - 2 a x \cdot \int \frac{1}{x ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 a x \frac{1}{x} \cdot \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= - 2 a x \frac{1}{x} arctan (u)

Substitute back

u = \frac{y}{x}

= - 2 a x \frac{1}{x} arctan (\frac{y}{x})

Simplify

- 2 a x \frac{1}{x} arctan (\frac{y}{x}) : - 2 a arctan (\frac{y}{x})

= - 2 a arctan (\frac{y}{x})

Add a constant to the solution

= - 2 a arctan (\frac{y}{x}) + C

\frac{d}{d x} (\frac{1}{2} x^{2} + x^{- 1})

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y^{^{''}} - 3 y^{^{'}} + 2 y = 2 t^{3}

What is the integral of (-2ax)/(x^2+y^2) ?
The integral of (-2ax)/(x^2+y^2) is -2aarctan(y/x)+C