What is the derivative of ln(8x+7) ?

The derivative of ln(8x+7) is 8/(8x+7)

What is the first derivative of ln(8x+7) ?

The first derivative of ln(8x+7) is 8/(8x+7)

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\frac{d}{d x} (ln (8 x + 7))

\frac{8}{8 x + 7}

Solution steps

\frac{d}{d x} (ln (8 x + 7))

Apply the chain rule:

\frac{1}{8 x + 7} \frac{d}{d x} (8 x + 7)

= \frac{1}{8 x + 7} \frac{d}{d x} (8 x + 7)

\frac{d}{d x} (8 x + 7) = 8

= \frac{1}{8 x + 7} \cdot 8

Simplify

\frac{1}{8 x + 7} \cdot 8 : \frac{8}{8 x + 7}

= \frac{8}{8 x + 7}

\int \frac{20}{e ^{\frac{x}{5}}} d x

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\int \frac{x ^{2} - 81}{x} d x

\int \frac{( x ^{2} - 1 )}{( x ^{2} + 1 ) ( x - 2 )} d x

\frac{\partial}{\partial x} (\frac{5 x - 3 y}{5 x + 3 y})

What is the derivative of ln(8x+7) ?
The derivative of ln(8x+7) is 8/(8x+7)
What is the first derivative of ln(8x+7) ?
The first derivative of ln(8x+7) is 8/(8x+7)