What is the derivative of g(x)=(sin(8x))/(cos(x)) ?

The derivative of g(x)=(sin(8x))/(cos(x)) is cos(8x)*8sec(x)+sec(x)tan(x)sin(8x)

What is the first derivative of g(x)=(sin(8x))/(cos(x)) ?

The first derivative of g(x)=(sin(8x))/(cos(x)) is cos(8x)*8sec(x)+sec(x)tan(x)sin(8x)

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derivative of

g (x) = \frac{sin ( 8 x )}{cos ( x )}

cos (8 x) \cdot 8 sec (x) + sec (x) tan (x) sin (8 x)

Solution steps

\frac{d}{d x} (\frac{sin ( 8 x )}{cos ( x )})

Simplify

\frac{sin ( 8 x )}{cos ( x )} : sin (8 x) sec (x)

= \frac{d}{d x} (sin (8 x) sec (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (8 x), g = sec (x)

= \frac{d}{d x} (sin (8 x)) sec (x) + \frac{d}{d x} (sec (x)) sin (8 x)

\frac{d}{d x} (sin (8 x)) = cos (8 x) \cdot 8

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= cos (8 x) \cdot 8 sec (x) + sec (x) tan (x) sin (8 x)

\int_{1}^{\infty} - \frac{1}{x} d x

(cos (3 x)) y^{^{'}} - 3 (tan (3 x)) y = - 10 sec (3 x)

(t + 1) cos (- t)

\int - 2 cos^{2} (x) sin (x) d x

\frac{d v}{d t} = 32 - \frac{4}{5} v

What is the derivative of g(x)=(sin(8x))/(cos(x)) ?
The derivative of g(x)=(sin(8x))/(cos(x)) is cos(8x)*8sec(x)+sec(x)tan(x)sin(8x)
What is the first derivative of g(x)=(sin(8x))/(cos(x)) ?
The first derivative of g(x)=(sin(8x))/(cos(x)) is cos(8x)*8sec(x)+sec(x)tan(x)sin(8x)