What is the derivative of 9e^{4x} ?

The derivative of 9e^{4x} is 36e^{4x}

What is the first derivative of 9e^{4x} ?

The first derivative of 9e^{4x} is 36e^{4x}

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\frac{d}{d x} (9 e^{4 x})

36 e^{4 x}

Solution steps

\frac{d}{d x} (9 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 9 e^{4 x} \cdot 4

Simplify

= 36 e^{4 x}

\frac{\partial}{\partial x} (\frac{2 x ^{2} + 7 x ^{2} y}{3 x y})

x \to 6 lim (\frac{1}{x - 6})

n = 0 \sum \infty 1 8^{n} x^{n} n!

(ln ∣ x ∣)^{^{'}}

f (x) = x^{11} arccot (x)

What is the derivative of 9e^{4x} ?
The derivative of 9e^{4x} is 36e^{4x}
What is the first derivative of 9e^{4x} ?
The first derivative of 9e^{4x} is 36e^{4x}