What is (\partial)/(\partial y)(sin(x)+picos(y)) ?

The answer to (\partial)/(\partial y)(sin(x)+picos(y)) is -pisin(y)

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(\partial)/(\partial y)(sin(x)+picos(y))

\frac{\partial}{\partial y} (sin (x) + π cos (y))

- π sin (y)

Solution steps

\frac{\partial}{\partial y} (sin (x) + π cos (y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (sin (x)) + \frac{\partial}{\partial y} (π cos (y))

\frac{\partial}{\partial y} (sin (x)) = 0

\frac{\partial}{\partial y} (π cos (y)) = - π sin (y)

= 0 - π sin (y)

Simplify

= - π sin (y)

2 v^{'} t (x) = v

\int \frac{( 1 - y ) e ^{y}}{y ^{2}} d y

y (8 x - 9 y) d x + 2 x (x - 3 y) d y = 0

\frac{d}{d x} (a x \cdot e^{b x})

f (x) = (11 x - 1)^{- \frac{1}{5}}, at x = 3

What is (\partial)/(\partial y)(sin(x)+picos(y)) ?
The answer to (\partial)/(\partial y)(sin(x)+picos(y)) is -pisin(y)