What is the derivative of 16in(x^2-x^2) ?

The derivative of 16in(x^2-x^2) is 32inx-2x

What is the first derivative of 16in(x^2-x^2) ?

The first derivative of 16in(x^2-x^2) is 32inx-2x

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\frac{d}{d x} (16 in (x^{2}) - x^{2})

32 in x - 2 x

Solution steps

\frac{d}{d x} (16 in (x^{2}) - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (16 in x^{2}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (16 in x^{2}) = 32 in x

\frac{d}{d x} (x^{2}) = 2 x

= 32 in x - 2 x

f (x) = \frac{1}{x - 1}, at x = 3

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What is the derivative of 16in(x^2-x^2) ?
The derivative of 16in(x^2-x^2) is 32inx-2x
What is the first derivative of 16in(x^2-x^2) ?
The first derivative of 16in(x^2-x^2) is 32inx-2x