What is the derivative of sin(x^2+pi) ?

The derivative of sin(x^2+pi) is -cos(x^2)*2x

What is the first derivative of sin(x^2+pi) ?

The first derivative of sin(x^2+pi) is -cos(x^2)*2x

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derivative of

sin (x^{2} + π)

- cos (x^{2}) \cdot 2 x

Solution steps

\frac{d}{d x} (sin (x^{2} + π))

Simplify

sin (x^{2} + π) : - sin (x^{2})

= \frac{d}{d x} (- sin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (x^{2}))

Apply the chain rule:

cos (x^{2}) \frac{d}{d x} (x^{2})

= cos (x^{2}) \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - cos (x^{2}) \cdot 2 x

2 x - \frac{1}{2 x}

y = arcsin (x^{4})

\frac{\partial}{\partial x} (\frac{1}{( 1 + x )})

(x^{2} - 3 x + 1) 25 - x^{2}

x \to 1 lim (7 e^{x - 1})

What is the derivative of sin(x^2+pi) ?
The derivative of sin(x^2+pi) is -cos(x^2)*2x
What is the first derivative of sin(x^2+pi) ?
The first derivative of sin(x^2+pi) is -cos(x^2)*2x