What is (\partial)/(\partial x)(2x+y+1) ?

The answer to (\partial)/(\partial x)(2x+y+1) is 2

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(\partial)/(\partial x)(2x+y+1)

\frac{\partial}{\partial x} (2 x + y + 1)

2

Solution steps

\frac{\partial}{\partial x} (2 x + y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (1) = 0

= 2 + 0 + 0

Simplify

= 2

\int \frac{3 x ^{2} - 7}{x ^{3} - 7 x + 6} d x

\int_{0}^{1} (t 4 + 9 t^{2}) d t

x + 2 y = x + 2 y = 8

y^{^{'}} = 5 x (x - 3)

\frac{d y}{d x} = \frac{1}{3} (x^{2} + 2)^{\frac{3}{2}}

What is (\partial)/(\partial x)(2x+y+1) ?
The answer to (\partial)/(\partial x)(2x+y+1) is 2