What is the derivative of 104-80e^{-0.2t} ?

The derivative of 104-80e^{-0.2t} is 16e^{-0.2t}

What is the first derivative of 104-80e^{-0.2t} ?

The first derivative of 104-80e^{-0.2t} is 16e^{-0.2t}

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derivative of

104 - 80 e^{- 0.2 t}

16 e^{- 0.2 t}

Solution steps

\frac{d}{d t} (104 - 80 e^{- 0.2 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (104) - \frac{d}{d t} (80 e^{- 0.2 t})

\frac{d}{d t} (104) = 0

\frac{d}{d t} (80 e^{- 0.2 t}) = - 16 e^{- 0.2 t}

= 0 - (- 16 e^{- 0.2 t})

Simplify

= 16 e^{- 0.2 t}

arcsin (2 x + 1)

\int e^{(- \frac{x ^{2}}{4})} d x

\frac{d y}{d t} = \frac{t}{y - 2}

\int cot (x) csc (x) d x

\frac{d}{d x} (x - 8)

What is the derivative of 104-80e^{-0.2t} ?
The derivative of 104-80e^{-0.2t} is 16e^{-0.2t}
What is the first derivative of 104-80e^{-0.2t} ?
The first derivative of 104-80e^{-0.2t} is 16e^{-0.2t}