What is the derivative of x^2e^x-2xe^x+5e^x ?

The derivative of x^2e^x-2xe^x+5e^x is e^xx^2+3e^x

What is the first derivative of x^2e^x-2xe^x+5e^x ?

The first derivative of x^2e^x-2xe^x+5e^x is e^xx^2+3e^x

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derivative of

x^{2} e^{x} - 2 x e^{x} + 5 e^{x}

e^{x} x^{2} + 3 e^{x}

Solution steps

\frac{d}{d x} (x^{2} e^{x} - 2 x e^{x} + 5 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} e^{x}) - \frac{d}{d x} (2 x e^{x}) + \frac{d}{d x} (5 e^{x})

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 5 e^{x}

Simplify

2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 5 e^{x} : e^{x} x^{2} + 3 e^{x}

= e^{x} x^{2} + 3 e^{x}

x \to 0 lim (\frac{x ^{2} + 5 x}{x})

x y^{^{'}} = y + x

\int ∣ 2 x - 3 ∣ d x

y^{^{''}} + 6 y^{^{'}} = - 108 cos (6 x)

\int \frac{( 5 sin ^{3} ( x ) )}{cos ( x )} d x

What is the derivative of x^2e^x-2xe^x+5e^x ?
The derivative of x^2e^x-2xe^x+5e^x is e^xx^2+3e^x
What is the first derivative of x^2e^x-2xe^x+5e^x ?
The first derivative of x^2e^x-2xe^x+5e^x is e^xx^2+3e^x