What is the tangent of f(x)=x^4,(2,16) ?

The tangent of f(x)=x^4,(2,16) is y=32x-48

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tangent of f(x)=x^4,(2,16)

tangent of

f (x) = x^{4}, (2, 16)

y = 32 x - 48

Solution steps

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

(2, 16) : m = 32

Find the line with slope m=

32

and passing through

(2, 16) : y = 32 x - 48

y = 32 x - 48

x \to 0 lim (+ (x))

\int \frac{1}{( \frac{x}{2} ) ^{2} + 1} d x

\frac{d}{d x} (\frac{e ^{2 x} - 1}{x})

\frac{d}{d x} (a y (x))

What is the tangent of f(x)=x^4,(2,16) ?
The tangent of f(x)=x^4,(2,16) is y=32x-48