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Popular >

integral from 0 to 1 of (x^3+x)

Solution

\int_{0}^{1} (x^{3} + x) d x

Solution

\frac{3}{4}

+1

Decimal Notation

0.75

Solution steps

\int_{0}^{1} x^{3} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x + \int_{0}^{1} x d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} x d x = \frac{1}{2}

= \frac{1}{4} + \frac{1}{2}

Simplify

\frac{1}{4} + \frac{1}{2} : \frac{3}{4}

= \frac{3}{4}

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\int 2 x yz d y

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\frac{\partial}{\partial y} (y - \frac{1}{x})

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x \to 2 + lim (3)

laplacetransform t^3e^{-,\at}laplace transform

t^{3} e^{-, at}

integral of x/(sqrt(6x+1))

\int \frac{x}{6 x + 1} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x^3+x) ?
The integral from 0 to 1 of (x^3+x) is 3/4