What is the tangent of 7/x ,\at x=6 ?

The tangent of 7/x ,\at x=6 is y=-7/36 x+7/3

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tangent of 7/x ,\at x=6

tangent of

\frac{7}{x}, at x = 6

y = - \frac{7}{36} x + \frac{7}{3}

Solution steps

Find the tangent point:

(6, \frac{7}{6})

Find the slope of

y = \frac{7}{x} : \frac{d y}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

y = \frac{7}{x}

x = 6 : m = - \frac{7}{36}

Find the line with slope m=

- \frac{7}{36}

and passing through

(6, \frac{7}{6}) : y = - \frac{7}{36} x + \frac{7}{3}

y = - \frac{7}{36} x + \frac{7}{3}

\frac{\partial}{\partial x} (sin (- x) cos (8 y))

2 tan (cos (x))

\int \frac{cos ( y )}{sin ( y )} d y

y = \frac{2 x}{x ^{2} + 1}

\int t^{2} (t - \frac{2}{t}) d t

What is the tangent of 7/x ,\at x=6 ?
The tangent of 7/x ,\at x=6 is y=-7/36 x+7/3