What is (\partial)/(\partial y)(ycos(xy)) ?

The answer to (\partial)/(\partial y)(ycos(xy)) is cos(yx)-yxsin(yx)

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(\partial)/(\partial y)(ycos(xy))

\frac{\partial}{\partial y} (y cos (x y))

cos (y x) - y x sin (y x)

Solution steps

\frac{\partial}{\partial y} (y cos (x y))

Treat

x

as a constant

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = cos (x y)

= \frac{\partial}{\partial y} (y) cos (x y) + \frac{\partial}{\partial y} (cos (x y)) y

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (cos (x y)) = - sin (x y) x

= 1 \cdot cos (x y) + (- sin (x y) x) y

Simplify

= cos (y x) - y x sin (y x)

\int \frac{e ^{x}}{5 - e ^{2 x}} d x

x \to \infty lim (- \frac{3}{2} x)

x \to - 2 + lim (\frac{x ^{2} - 9}{x ^{2} - 2 x - 8})

n = 1 \sum \infty \frac{9 ^{n}}{n !}

x \to \infty lim (3 x + x^{2})

What is (\partial)/(\partial y)(ycos(xy)) ?
The answer to (\partial)/(\partial y)(ycos(xy)) is cos(yx)-yxsin(yx)