What is the derivative of (sqrt(x-1))+(2x-2) ?

The derivative of (sqrt(x-1))+(2x-2) is 1/(2sqrt(x-1))+2

What is the first derivative of (sqrt(x-1))+(2x-2) ?

The first derivative of (sqrt(x-1))+(2x-2) is 1/(2sqrt(x-1))+2

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derivative of

(x - 1) + (2 x - 2)

\frac{1}{2 x - 1} + 2

Solution steps

\frac{d}{d x} (x - 1 + 2 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x - 1) + \frac{d}{d x} (2 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x - 1) = \frac{1}{2 x - 1}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= \frac{1}{2 x - 1} + 2 - 0

Simplify

= \frac{1}{2 x - 1} + 2

\frac{\partial}{\partial x} (x cos (x + 2 y) \cdot 2)

\frac{d}{d x} (x \cdot cos (y))

x \to 0 lim (\frac{cot ( π x ) sin ( x )}{2 sec ( x )})

\int cos (3 t) d t

\frac{d}{d x} (2 f (x))

What is the derivative of (sqrt(x-1))+(2x-2) ?
The derivative of (sqrt(x-1))+(2x-2) is 1/(2sqrt(x-1))+2
What is the first derivative of (sqrt(x-1))+(2x-2) ?
The first derivative of (sqrt(x-1))+(2x-2) is 1/(2sqrt(x-1))+2