What is the integral from-2 to 0 of (5x^2+5x) ?

The integral from-2 to 0 of (5x^2+5x) is 10/3

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integral from-2 to 0 of (5x^2+5x)

\int_{- 2}^{0} (5 x^{2} + 5 x) d x

\frac{10}{3}

Decimal Notation

3.33333 \dots

Solution steps

\int_{- 2}^{0} 5 x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 5 x^{2} d x + \int_{- 2}^{0} 5 x d x

\int_{- 2}^{0} 5 x^{2} d x = \frac{40}{3}

\int_{- 2}^{0} 5 x d x = - 10

= \frac{40}{3} - 10

Simplify

\frac{40}{3} - 10 : \frac{10}{3}

= \frac{10}{3}

x \to \infty lim (5 x^{3})

\frac{d}{d x} (\frac{2 x + 1}{x - 1})

\frac{d}{d x} (\frac{y}{x})

\frac{d}{d x} (arcsin (\frac{a x}{4}))

\frac{\partial}{\partial y} (- 5 e^{x} cos (yz))

What is the integral from-2 to 0 of (5x^2+5x) ?
The integral from-2 to 0 of (5x^2+5x) is 10/3