What is the limit as x approaches 0 of x^4sin(1/x) ?

The limit as x approaches 0 of x^4sin(1/x) is 0

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limit as x approaches 0 of x^4sin(1/x)

x \to 0 lim (x^{4} sin (\frac{1}{x}))

0

Solution steps

x \to 0 lim (x^{4} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\frac{s + 2}{s + 3}

\frac{d}{d x} (x^{5} + 5 x^{4} - 10 x^{2} + 6)

\frac{d y}{d x}, 2 x^{4} + 9 y = 2 x^{2} y + 36

\frac{\partial}{\partial x} (x^{2} + x y + y^{2} - 2 x + 2 y)

\frac{( s )}{s ^{2} + 5 s + 6}

What is the limit as x approaches 0 of x^4sin(1/x) ?
The limit as x approaches 0 of x^4sin(1/x) is 0