What is the derivative of f(x)=sqrt(17.198^2-x^2) ?

The derivative of f(x)=sqrt(17.198^2-x^2) is -x/(sqrt(295.771204-x^2))

What is the first derivative of f(x)=sqrt(17.198^2-x^2) ?

The first derivative of f(x)=sqrt(17.198^2-x^2) is -x/(sqrt(295.771204-x^2))

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derivative of

f (x) = 17.19 8^{2} - x^{2}

- \frac{x}{295.771204 - x ^{2}}

Solution steps

\frac{d}{d x} (17.19 8^{2} - x^{2})

Apply the chain rule:

\frac{1}{2 17.19 8 ^{2} - x ^{2}} \frac{d}{d x} (17.19 8^{2} - x^{2})

= \frac{1}{2 17.19 8 ^{2} - x ^{2}} \frac{d}{d x} (17.19 8^{2} - x^{2})

\frac{d}{d x} (17.19 8^{2} - x^{2}) = - 2 x

= \frac{1}{2 17.19 8 ^{2} - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 17.19 8 ^{2} - x ^{2}} (- 2 x) : - \frac{x}{295.771204 - x ^{2}}

= - \frac{x}{295.771204 - x ^{2}}

\int sec^{3} (π x) d x

\frac{d}{d x} (e^{x e^{y}})

\frac{d}{d x} (- cot (2 x))

\frac{d}{d x} (cos (x^{2}))

\frac{d y}{d x} = \frac{6}{5} (1 - \frac{y}{8})

What is the derivative of f(x)=sqrt(17.198^2-x^2) ?
The derivative of f(x)=sqrt(17.198^2-x^2) is -x/(sqrt(295.771204-x^2))
What is the first derivative of f(x)=sqrt(17.198^2-x^2) ?
The first derivative of f(x)=sqrt(17.198^2-x^2) is -x/(sqrt(295.771204-x^2))