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Popular >

2y^'=0

Solution

2 y^{^{'}} = 0

Solution

y = c_{1}

Solution steps

2 y^{'} (t) = 0

Isolate

y^{'} (t) : y^{'} (t) = 0

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 0 d t

\int 0 d t = c_{1}

y = c_{1}

Popular Examples

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y = \frac{x ^{5} - 8 x}{x ^{3}}, (1, 4)

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n = 2 \sum \infty \frac{4}{n ^{2} - 1}

derivative of f(x)=5.2x+2.3 derivative of

f (x) = 5.2 x + 2.3

integral of ((e^{2x}))/(1+e^{2x)}

\int \frac{( e ^{2 x} )}{1 + e ^{2 x}} d x

(dy)/(dx)+y/x =3x^6y^2

\frac{d y}{d x} + \frac{y}{x} = 3 x^{6} y^{2}

Frequently Asked Questions (FAQ)

What is the solution for 2y^'=0 ?
The solution for 2y^'=0 is y=c_{1}