What is the derivative of y=sqrt(\sqrt{\sqrt{x)}} ?

The derivative of y=sqrt(\sqrt{\sqrt{x)}} is 1/(8\sqrt[8]{x)x^{3/4}}

What is the first derivative of y=sqrt(\sqrt{\sqrt{x)}} ?

The first derivative of y=sqrt(\sqrt{\sqrt{x)}} is 1/(8\sqrt[8]{x)x^{3/4}}

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derivative of

y = x

Solution steps

\frac{d}{d x} (x)

Apply the chain rule:

\frac{1}{2 x} \frac{d}{d x} (x)

= \frac{1}{2 x} \frac{d}{d x} (x)

\frac{d}{d x} (x) = \frac{1}{4 x ^{\frac{3}{4}}}

= \frac{1}{2 x} \cdot \frac{1}{4 x ^{\frac{3}{4}}}

Simplify

\frac{\partial}{\partial s} (t^{2} - 2 s^{2})

\int 7 t^{8} d t

y^{^{''}} + 2 y^{^{'}} + 2 y = 3 cos (t) - sin (t)

\int_{1}^{3} x e^{- x^{2}} d x

\frac{d}{d x} (\frac{x - 3}{x ^{2} + 4})

What is the derivative of y=sqrt(\sqrt{\sqrt{x)}} ?
The derivative of y=sqrt(\sqrt{\sqrt{x)}} is 1/(8\sqrt[8]{x)x^{3/4}}
What is the first derivative of y=sqrt(\sqrt{\sqrt{x)}} ?
The first derivative of y=sqrt(\sqrt{\sqrt{x)}} is 1/(8\sqrt[8]{x)x^{3/4}}