What is the derivative of-2x^2+7x+5 ?

The derivative of-2x^2+7x+5 is -4x+7

What is the first derivative of-2x^2+7x+5 ?

The first derivative of-2x^2+7x+5 is -4x+7

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\frac{d}{d x} (- 2 x^{2} + 7 x + 5)

- 4 x + 7

Solution steps

\frac{d}{d x} (- 2 x^{2} + 7 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (7 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (5) = 0

= - 4 x + 7 + 0

Simplify

= - 4 x + 7

n = 0 \sum \infty ln (1 + n)

\frac{\partial}{\partial y} (x^{y} - y^{x})

y = (x^{2} - 7 x + 7) e^{\frac{9 x}{7}}

\int_{0}^{\infty} cos (x) d x

\int (6 x^{2} + 8 x + 3) d x

What is the derivative of-2x^2+7x+5 ?
The derivative of-2x^2+7x+5 is -4x+7
What is the first derivative of-2x^2+7x+5 ?
The first derivative of-2x^2+7x+5 is -4x+7