What is the derivative of x^2y^2 ?

The derivative of x^2y^2 is 2xy^2

What is the first derivative of x^2y^2 ?

The first derivative of x^2y^2 is 2xy^2

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derivative of

x^{2} y^{2}

2 x y^{2}

Solution steps

\frac{d}{d x} (x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{2}

\int 2 x y e^{x^{2} y} d x

\frac{d}{d t} (3 t^{2})

\frac{d}{d x} (- 4 e^{- x^{2}} x)

\frac{\partial}{\partial x} ((5 x + 4 y) e^{y})

5 x^{2} - 4 x + 5

What is the derivative of x^2y^2 ?
The derivative of x^2y^2 is 2xy^2
What is the first derivative of x^2y^2 ?
The first derivative of x^2y^2 is 2xy^2