What is (\partial)/(\partial x)(5cos(x)) ?

The answer to (\partial)/(\partial x)(5cos(x)) is -5sin(x)

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(\partial)/(\partial x)(5cos(x))

\frac{\partial}{\partial x} (5 cos (x))

- 5 sin (x)

Solution steps

\frac{\partial}{\partial x} (5 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 5 (- sin (x))

Simplify

= - 5 sin (x)

\int 2 x (x^{2} + 1)^{- 5} d x

\frac{\partial}{\partial x} (\frac{a x}{y ^{2}})

\int \frac{( x + 4 )}{x ^{3} + 3 x ^{2} + 2 x} d x

t^{2} y^{^{''}} + 5 t y^{^{'}} + 4 y = 0

x \to 1 + lim (\frac{x - 1}{x - 1})

What is (\partial)/(\partial x)(5cos(x)) ?
The answer to (\partial)/(\partial x)(5cos(x)) is -5sin(x)