What is the integral of (-4)/(x^2) ?

The integral of (-4)/(x^2) is 4/x+C

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integral of (-4)/(x^2)

\int \frac{- 4}{x ^{2}} d x

\frac{4}{x} + C

Solution steps

\int \frac{- 4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 4 (- \frac{1}{x})

Simplify

- 4 (- \frac{1}{x}) : \frac{4}{x}

= \frac{4}{x}

Add a constant to the solution

= \frac{4}{x} + C

y = \frac{2 x - 3}{4 x + 1}

\frac{\partial}{\partial x} (3 (x - y) \cdot e^{3 y + 2 x^{2}})

\frac{t}{1 + t ^{2}}

\int \frac{x ^{4}}{4 x ^{2} + 1} d x

\int_{1}^{2} (x^{2} + 3 x^{4}) d x