What is the derivative of 2x+3x^2 ?

The derivative of 2x+3x^2 is 2+6x

What is the first derivative of 2x+3x^2 ?

The first derivative of 2x+3x^2 is 2+6x

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\frac{d}{d x} (2 x + 3 x^{2})

2 + 6 x

Solution steps

\frac{d}{d x} (2 x + 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{2}) = 6 x

= 2 + 6 x

\frac{d ^{2}}{d x ^{2}} (ln (2 x + 4))

y = x^{2}, y = 20 - x

\int csc^{2} (\frac{x}{6}) d x

\frac{d}{d x} (2 x^{- 3} + x - 8 x + 15)

y^{^{''}} + 4 y = cos (2 x) + sin (2 x)

What is the derivative of 2x+3x^2 ?
The derivative of 2x+3x^2 is 2+6x
What is the first derivative of 2x+3x^2 ?
The first derivative of 2x+3x^2 is 2+6x