What is the solution for (dy)/(dx)=e^{3x+2y} ?

The solution for (dy)/(dx)=e^{3x+2y} is y=-(ln(-2/3 e^{3x}-c_{1}))/2

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(dy)/(dx)=e^{3x+2y}

\frac{d y}{d x} = e^{3 x + 2 y}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{3 x + 2 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

n \to \infty lim (\frac{n}{6} sin (\frac{6}{n}))

\int_{0}^{1} (x + 1) e^{x^{2} + 2 x} d x

\int e^{t a n (5 x)} sec^{2} (5 x) d x

\frac{d y}{d x} = - \frac{( x + y ) ^{2}}{2 x y + x ^{2} - 1}

\frac{d}{d x} (\frac{( 1 - 2 x )}{1 + 2 x})

What is the solution for (dy)/(dx)=e^{3x+2y} ?
The solution for (dy)/(dx)=e^{3x+2y} is y=-(ln(-2/3 e^{3x}-c_{1}))/2