What is the tangent of f(x)=6sqrt(x),(9,18) ?

The tangent of f(x)=6sqrt(x),(9,18) is y=x+9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=6sqrt(x),(9,18)

tangent of

f (x) = 6 x, (9, 18)

y = x + 9

Solution steps

Find the slope of

f (x) = 6 x : \frac{df ( x )}{d x} = \frac{3}{x}

Compute the slope of

f (x) = 6 x

(9, 18) : m = 1

Find the line with slope m=

1

and passing through

(9, 18) : y = x + 9

y = x + 9

f (x) = tan^{3} (x)

y^{^{''}} + 1 y^{^{'}} + 0.25 y = 0

\frac{d}{d x} ((\frac{x - 3}{2 x + 1})^{4})

\int_{12}^{13} x x^{2} - 144 d x

\frac{\partial}{\partial x} (x y - ln (x y))

What is the tangent of f(x)=6sqrt(x),(9,18) ?
The tangent of f(x)=6sqrt(x),(9,18) is y=x+9