What is the derivative of f(x)= 1/((x+3)^2) ?

The derivative of f(x)= 1/((x+3)^2) is -2/((x+3)^3)

What is the first derivative of f(x)= 1/((x+3)^2) ?

The first derivative of f(x)= 1/((x+3)^2) is -2/((x+3)^3)

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derivative of

f (x) = \frac{1}{( x + 3 ) ^{2}}

- \frac{2}{( x + 3 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x + 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

= - \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - \frac{2}{( x + 3 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x + 3 ) ^{3}}

3 x^{2} - 5 x

x \to 0 lim (∣ x + 1 ∣)

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\int (x + x^{- 2}) d x

\frac{\partial}{\partial x} (lo g_{10} (x + y))

What is the derivative of f(x)= 1/((x+3)^2) ?
The derivative of f(x)= 1/((x+3)^2) is -2/((x+3)^3)
What is the first derivative of f(x)= 1/((x+3)^2) ?
The first derivative of f(x)= 1/((x+3)^2) is -2/((x+3)^3)