What is the limit as x approaches 3 of 2/(x^2-9) ?

The limit as x approaches 3 of 2/(x^2-9) is diverges

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limit as x approaches 3 of 2/(x^2-9)

x \to 3 lim (\frac{2}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{2}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{2}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{2}{x ^{2} - 9}) = - \infty

= diverges

y = x, 4 x + y^{2} = 12

{\frac{5}{s ^{2} + 49}}

(a + 3 y^{2} + b)^{\frac{1}{2}}

f (x) = \frac{π ^{2}}{x ^{2} + 4 x}

\int - \frac{1}{27} sin (3 x) d x

What is the limit as x approaches 3 of 2/(x^2-9) ?
The limit as x approaches 3 of 2/(x^2-9) is diverges