What is the derivative of-1/(x+1) ?

The derivative of-1/(x+1) is 1/((x+1)^2)

What is the first derivative of-1/(x+1) ?

The first derivative of-1/(x+1) is 1/((x+1)^2)

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\frac{d}{d x} (- \frac{1}{x + 1})

\frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (- \frac{1}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

= \frac{1}{( x + 1 ) ^{2}}

\frac{d}{d s} (s L (y (s)))

\int \frac{1}{2 x ^{2} - 12 x + 26} d x

\int \frac{1 + arctan ( x )}{1 + x ^{2}} d x

\frac{\partial}{\partial y} (\frac{1}{2} (x - y)^{2})

x \to 2 lim (x^{2} - 4 x + 2)

What is the derivative of-1/(x+1) ?
The derivative of-1/(x+1) is 1/((x+1)^2)
What is the first derivative of-1/(x+1) ?
The first derivative of-1/(x+1) is 1/((x+1)^2)