What is the integral of (\sqrt[3]{x}+1/(sqrt(x))) ?

The integral of (\sqrt[3]{x}+1/(sqrt(x))) is 3/4 x^{4/3}+2sqrt(x)+C

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integral of (\sqrt[3]{x}+1/(sqrt(x)))

\frac{3}{4} x^{\frac{4}{3}} + 2 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int \frac{1}{x} d x = 2 x

= \frac{3}{4} x^{\frac{4}{3}} + 2 x

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + 2 x + C

f (x) = \frac{x}{1 + x ^{2}}, (2, 0.4)

\int_{0}^{2} (x + 2) - x^{2} d x

\frac{d}{d x} ((1 - sin (x))^{- \frac{1}{2}})

\frac{d}{d x} (ln (\frac{x}{3}) (x - 3))

\int \frac{361}{x ^{3} - 19 x ^{2}} d x

What is the integral of (\sqrt[3]{x}+1/(sqrt(x))) ?
The integral of (\sqrt[3]{x}+1/(sqrt(x))) is 3/4 x^{4/3}+2sqrt(x)+C