What is the derivative of (3x^2+3x-1^4) ?

The derivative of (3x^2+3x-1^4) is 4(3x^2+3x-1)^3(6x+3)

What is the first derivative of (3x^2+3x-1^4) ?

The first derivative of (3x^2+3x-1^4) is 4(3x^2+3x-1)^3(6x+3)

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\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

Solution steps

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

= 4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

\frac{d}{d x} (3 x^{2} + 3 x - 1) = 6 x + 3

= 4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

8 y^{^{''}} - 2 y^{^{'}} - y = 4 + 5 sin (2 t)

y = x^{2} - 3 x, y = 2 x + 6

f (x) = \frac{2 x}{e ^{x}}

n = 1 \sum \infty n! \cdot x^{n}

\frac{d}{d x} ((x + a) \cdot e^{2 x} + b)

What is the derivative of (3x^2+3x-1^4) ?
The derivative of (3x^2+3x-1^4) is 4(3x^2+3x-1)^3(6x+3)
What is the first derivative of (3x^2+3x-1^4) ?
The first derivative of (3x^2+3x-1^4) is 4(3x^2+3x-1)^3(6x+3)