What is the derivative of x^3+2x^2-4x+2 ?

The derivative of x^3+2x^2-4x+2 is 3x^2+4x-4

What is the first derivative of x^3+2x^2-4x+2 ?

The first derivative of x^3+2x^2-4x+2 is 3x^2+4x-4

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\frac{d}{d x} (x^{3} + 2 x^{2} - 4 x + 2)

3 x^{2} + 4 x - 4

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2} - 4 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 3 x^{2} + 4 x - 4 + 0

Simplify

= 3 x^{2} + 4 x - 4

k = 1 \sum \infty e^{- k}

x \to \infty lim (e^{x} - x)

3 v + \frac{d v}{d x} = 0

\int (4 + x^{8})^{5} 8 x^{7} d x

\int (sec^{2} (θ) + 7) d θ

What is the derivative of x^3+2x^2-4x+2 ?
The derivative of x^3+2x^2-4x+2 is 3x^2+4x-4
What is the first derivative of x^3+2x^2-4x+2 ?
The first derivative of x^3+2x^2-4x+2 is 3x^2+4x-4