What is the integral from-infinity to 0 of 1/(6-9x) ?

The integral from-infinity to 0 of 1/(6-9x) is diverges

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integral from-infinity to 0 of 1/(6-9x)

\int_{- \infty}^{0} \frac{1}{6 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{6 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{6 - 9 x} d x = - \frac{1}{9} ln ∣ 6 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{6 - 9 x} d x =

diverges

= diverges

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What is the integral from-infinity to 0 of 1/(6-9x) ?
The integral from-infinity to 0 of 1/(6-9x) is diverges