What is the integral from 1 to 4 of (sqrt(x)) ?

The integral from 1 to 4 of (sqrt(x)) is 14/3

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integral from 1 to 4 of (sqrt(x))

\int_{1}^{4} (x) d x

\frac{14}{3}

Decimal Notation

4.66666 \dots

Solution steps

\int_{1}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{4}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{4}

Compute the boundaries:

\frac{14}{3}

= \frac{14}{3}

\frac{d y}{d x} - \frac{y}{x} = 6 x e^{x}

y^{^{''}} + 4 y^{^{'}} + 4 y = t^{- 2} e^{- 2 t}

\frac{d}{d x} (tan (x^{2} - 1))

y^{^{''}} - y^{^{'}} - 20 y = 0

\frac{d ^{2}}{d x ^{2}} (3 x - 4 x^{\frac{9}{10}})

What is the integral from 1 to 4 of (sqrt(x)) ?
The integral from 1 to 4 of (sqrt(x)) is 14/3