What is implicit (dy)/(dx),x+y=x^2 ?

The answer to implicit (dy)/(dx),x+y=x^2 is (dy)/(dx)=2x-1

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implicit (dy)/(dx),x+y=x^2

implicit derivative

\frac{d y}{d x}, x + y = x^{2}

\frac{d y}{d x} = 2 x - 1

Solution steps

x + y = x^{2}

Treat

y

y (x)

Differentiate both sides:

1 + \frac{d y}{d x} = 2 x

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 2 x - 1

\frac{d y}{d x} = 2 x - 1

y^{^{''}} - 6 y^{^{'}} - 27 y = 0

\int \frac{1}{y - x} d y

\int (1. 8^{0.045 x} - 1) d x

f (x) = e^{\frac{x}{3}}

What is implicit (dy)/(dx),x+y=x^2 ?
The answer to implicit (dy)/(dx),x+y=x^2 is (dy)/(dx)=2x-1