What is the first derivative of y=x-1 ?

The first derivative of y=x-1 is 1

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derivative of y=x-1

derivative of

y = x - 1

1

Solution steps

\frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

\int \frac{8 x}{x ^{3} + x ^{2} - x - 1} d x

\frac{d}{d x} (- cos (2 x) \cdot 2)

\frac{\partial}{\partial y} (y^{2} e^{x y - 3})

x \to - 5 lim (\frac{3}{x + 5})