What is (\partial)/(\partial x)(8x^6y^7+6x^4y^8) ?

The answer to (\partial)/(\partial x)(8x^6y^7+6x^4y^8) is 48y^7x^5+24y^8x^3

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(\partial)/(\partial x)(8x^6y^7+6x^4y^8)

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

48 y^{7} x^{5} + 24 y^{8} x^{3}

Solution steps

\frac{\partial}{\partial x} (8 x^{6} y^{7} + 6 x^{4} y^{8})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{6} y^{7}) + \frac{\partial}{\partial x} (6 x^{4} y^{8})

\frac{\partial}{\partial x} (8 x^{6} y^{7}) = 48 y^{7} x^{5}

\frac{\partial}{\partial x} (6 x^{4} y^{8}) = 24 y^{8} x^{3}

= 48 y^{7} x^{5} + 24 y^{8} x^{3}

\int \frac{x + 3}{x ^{2} + 6 x + 7} d x

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x + 1})

\int e^{2 x} (cos (3 x)) d x

\int \frac{6}{cos ( x ) - 1} d x

2 y^{^{''}} + 3 y^{^{'}} - 2 y = cos (2 x)

What is (\partial)/(\partial x)(8x^6y^7+6x^4y^8) ?
The answer to (\partial)/(\partial x)(8x^6y^7+6x^4y^8) is 48y^7x^5+24y^8x^3